Nuprl Definition : nondecreasing 4,23

nondecreasing(f;k) == i:(k-1). f(i)f(i+1) 
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clarification:

nondecreasing(f;k) == i:{0..(k-1)}. f(i)f(i+1) 
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Definitionsx:AB(x), {i..j}, AB
FDL editor aliasesnondecreasing

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